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Common: CallLambdaTrampoline can return a value

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As it is currently written, CallLambdaTrampoline does not return a
value. However, some of the functions that are being wrapped may
return a value that the JIT is expected to understand. A compiler
*cough cough clang* may opt to alter %rax after the wrapped lambda
returns, e.g. popping a previous value, which can clobber the
return value. If we actually have a return value, then the compiler
must not clobber it.
This commit is contained in:
Jeffrey Pfau 2015-07-03 22:27:36 -07:00
parent 3fc070c4fc
commit c9a25f9484
2 changed files with 4 additions and 6 deletions
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5
Source/Core/Common/Arm64Emitter.h
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@ -711,10 +711,9 @@ public:
// (this method might be a thunk in the case of multi-inheritance) so we // (this method might be a thunk in the case of multi-inheritance) so we
// have to go through a trampoline function. // have to go through a trampoline function.
template <typename T, typename... Args> template <typename T, typename... Args>
static void CallLambdaTrampoline(const std::function<T(Args...)>* f, static T CallLambdaTrampoline(const std::function<T(Args...)>* f, Args... args)
Args... args)
{ {
(*f)(args...); return (*f)(args...);
} }
// This function expects you to have set up the state. // This function expects you to have set up the state.

5
Source/Core/Common/x64Emitter.h
View File

@ -971,10 +971,9 @@ public:
// (this method might be a thunk in the case of multi-inheritance) so we // (this method might be a thunk in the case of multi-inheritance) so we
// have to go through a trampoline function. // have to go through a trampoline function.
template <typename T, typename... Args> template <typename T, typename... Args>
static void CallLambdaTrampoline(const std::function<T(Args...)>* f, static T CallLambdaTrampoline(const std::function<T(Args...)>* f, Args... args)
Args... args)
{ {
(*f)(args...); return (*f)(args...);
} }
template <typename T, typename... Args> template <typename T, typename... Args>